eliminate one form of PythonObject::Reset()

Summary:
I'd like to eliminate all forms of Reset() and all public constructors
on these objects, so the only way to make them is with Take<> and Retain<>
and the only way to copy or move them is with actual c++ copy, move, or
assignment.

This is a simple place to start.

Reviewers: JDevlieghere, clayborg, labath, jingham

Reviewed By: labath

Subscribers: lldb-commits

Tags: #lldb

Differential Revision: https://reviews.llvm.org/D69080

llvm-svn: 375182
This commit is contained in:
Lawrence D'Anna
2019-10-17 22:22:09 +00:00
parent c86a6acaee
commit 03819d1c80
3 changed files with 15 additions and 37 deletions

View File

@@ -182,7 +182,8 @@ public:
Reset(type, py_obj);
}
PythonObject(const PythonObject &rhs) : m_py_obj(nullptr) { Reset(rhs); }
PythonObject(const PythonObject &rhs)
: PythonObject(PyRefType::Borrowed, rhs.m_py_obj) {}
PythonObject(PythonObject &&rhs) {
m_py_obj = rhs.m_py_obj;
@@ -197,19 +198,6 @@ public:
m_py_obj = nullptr;
}
void Reset(const PythonObject &rhs) {
if (!rhs.IsValid())
Reset();
else
Reset(PyRefType::Borrowed, rhs.m_py_obj);
}
// PythonObject is implicitly convertible to PyObject *, which will call the
// wrong overload. We want to explicitly disallow this, since a PyObject
// *always* owns its reference. Therefore the overload which takes a
// PyRefType doesn't make sense, and the copy constructor should be used.
void Reset(PyRefType type, const PythonObject &ref) = delete;
void Reset(PyRefType type, PyObject *py_obj) {
if (py_obj == m_py_obj)
return;
@@ -244,19 +232,9 @@ public:
return result;
}
PythonObject &operator=(const PythonObject &other) {
Reset(PyRefType::Borrowed, other.get());
return *this;
}
void Reset(PythonObject &&other) {
PythonObject &operator=(PythonObject other) {
Reset();
m_py_obj = other.m_py_obj;
other.m_py_obj = nullptr;
}
PythonObject &operator=(PythonObject &&other) {
Reset(std::move(other));
m_py_obj = std::exchange(other.m_py_obj, nullptr);
return *this;
}