Credit to @krzysz00 who discovered this subtle bug in `MemRefUtils`. The
problem is in `getLinearizedMemRefOffsetAndSize()` utility. In
particular, how this subroutine computes the linearized size of a memref
is incorrect when given a non-packed memref.
### Background
As context, in a packed memref of `memref<8x8xf32>`, we'd compute the
size by multiplying the size of dimensions together. This is implemented
by composing an affine_map of `affine_map<()[s0, s1] -> (s0 * s1)>` and
then computing the result of size via `%size = affine.apply #map()[%c8,
%c8]`.
However, this is wrong for a non-packed memref of `memref<8x8xf32,
strided<[1024, 1]>>`. Since the previous computed multiplication map
will only consider the dimension sizes, it'd continue to conclude that
the size of the non-packed memref to be 64.
### Solution
This PR come up with a fix such that the linearized size computation
take strides into consideration. It computes the maximum of (dim size *
dim stride) for each dimension. We'd compute the size via the affine_map
of `affine_map<()[stride0, size0, stride1] -> ((stride0 * size0), 1 *
size1)>` and then computing the size via `%size = affine.max
#map()[%stride0, %size0, %size1]`. In particular for the new non-packed
memref, the size will be derived as max(1024\*8, 1\*8) = 8192 (rather
than the wrong size 64 computed by packed memref equation).
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