2e5b701d93
The test reorders the basic blocks to be dis-contiguous in the address space and checks if the back trace contains the right symbol. Reviewed By: labath Differential Revision: https://reviews.llvm.org/D89179
19 lines
185 B
C
19 lines
185 B
C
int k = 1;
|
|
|
|
int bar() {
|
|
return 0;
|
|
}
|
|
|
|
int foo() {
|
|
return bar();
|
|
}
|
|
|
|
int main() {
|
|
// Control flow to create basic block sections.
|
|
if (k)
|
|
foo();
|
|
else
|
|
bar();
|
|
return 0;
|
|
}
|