The may get changed before specialization by RunSCCPSolver. In other words, the pass may change the function without specialization happens. Add test and comment to reveal this. And it may return No Changed if the function get changed by RunSCCPSolver before the specialization. It looks like a potential bug. Test Plan: check-all Reviewed By: https://reviews.llvm.org/D107622 Differential Revision: https://reviews.llvm.org/D107622
49 lines
1.4 KiB
LLVM
49 lines
1.4 KiB
LLVM
; Test function specialization wouldn't crash due to constant expression.
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; Note that this test case shows that function specialization pass would
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; transform the function even if no specialization happened.
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; RUN: opt -function-specialization -S < %s | FileCheck %s
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; CHECK: plus:
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; CHECK-NEXT: %{{.*}} = call i64 @func2(i64* getelementptr inbounds (%struct, %struct* @Global, i32 0, i32 3))
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; CHECK: minus:
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; CHECK-NEXT: %{{.*}} = call i64 @func2(i64* getelementptr inbounds (%struct, %struct* @Global, i32 0, i32 4))
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%struct = type { i8, i16, i32, i64, i64}
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@Global = internal constant %struct {i8 0, i16 1, i32 2, i64 3, i64 4}
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define internal i64 @zoo(i1 %flag) {
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entry:
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br i1 %flag, label %plus, label %minus
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plus:
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%arg = getelementptr %struct, %struct* @Global, i32 0, i32 3
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%tmp0 = call i64 @func2(i64* %arg)
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br label %merge
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minus:
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%arg2 = getelementptr %struct, %struct* @Global, i32 0, i32 4
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%tmp1 = call i64 @func2(i64* %arg2)
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br label %merge
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merge:
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%tmp2 = phi i64 [ %tmp0, %plus ], [ %tmp1, %minus]
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ret i64 %tmp2
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}
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define internal i64 @func2(i64 *%x) {
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entry:
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%val = ptrtoint i64* %x to i64
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ret i64 %val
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}
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define internal i64 @func(i64 *%x, i64 (i64*)* %binop) {
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entry:
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%tmp0 = call i64 %binop(i64* %x)
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ret i64 %tmp0
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}
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define i64 @main() {
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%1 = call i64 @zoo(i1 0)
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%2 = call i64 @zoo(i1 1)
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%3 = add i64 %1, %2
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ret i64 %3
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} |